Advertisements
Advertisements
प्रश्न
Determine the following polynomial has (x + 1) a factor:
x3 + x2 + x + 1
Advertisements
उत्तर
If (x + 1) is a factor of p(x) = x3 + x2 + x + 1, then p (−1) must be zero, otherwise (x + 1) is not a factor of p(x).
p(x) = x3 + x2 + x + 1
p(−1) = (−1)3 + (−1)2 + (−1) + 1
= − 1 + 1 − 1 + 1
= 0
Hence, x + 1 is a factor of this polynomial.
APPEARS IN
संबंधित प्रश्न
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = x2 + x + k
Factorise:
x3 – 3x2 – 9x – 5
Factorise:
2y3 + y2 – 2y – 1
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
Factorize the following polynomial.
(y + 2) (y – 3) (y + 8) (y + 3) + 56
Find the value of m so that 2x – 1 be a factor of 8x4 + 4x3 – 16x2 + 10x + m.
Factorise:
x2 + 9x + 18
Factorise the following:
9x2 – 12x + 3
Factorise the following:
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
Factorise:
`2sqrt(2)a^3 + 8b^3 - 27c^3 + 18sqrt(2)abc`
