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प्रश्न
Factorise the following:
1 – 64a3 – 12a + 48a2
योग
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उत्तर
1 – 64a3 – 12a + 48a2 = (1)3 – (4a)3 – 3 × 12 × 4a + 3 × 1 × (4a)2
= (1 – 4a)3 ...[Using identity, (a – b)3 = a3 – b3 – 3a2b + 3ab2]
= (1 – 4a)(1 – 4a)(1 – 4a)
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Factorisation of Polynomials
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Polynomials - Exercise 2.3 [पृष्ठ २१]
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