Advertisements
Advertisements
प्रश्न
Factorise the following:
1 – 64a3 – 12a + 48a2
Advertisements
उत्तर
1 – 64a3 – 12a + 48a2 = (1)3 – (4a)3 – 3 × 12 × 4a + 3 × 1 × (4a)2
= (1 – 4a)3 ...[Using identity, (a – b)3 = a3 – b3 – 3a2b + 3ab2]
= (1 – 4a)(1 – 4a)(1 – 4a)
APPEARS IN
संबंधित प्रश्न
Determine the following polynomial has (x + 1) a factor:
x3 + x2 + x + 1
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 − 4x2 + x + 6, g(x) = x − 3
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = `2x^2+kx+sqrt2`
Determine the following polynomial has (x + 1) a factor:
x4 + 3x3 + 3x2 + x + 1
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
Find the factor of the polynomial given below.
2m2 + 5m – 3
Factorize the following polynomial.
(y2 + 5y) (y2 + 5y – 2) – 24
Show that 2x – 3 is a factor of x + 2x3 – 9x2 + 12.
If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Factorise:
a3 – 8b3 – 64c3 – 24abc
