Advertisements
Advertisements
प्रश्न
Show that 2x – 3 is a factor of x + 2x3 – 9x2 + 12.
Advertisements
उत्तर
Let p(x) = 2x3 – 9x2 + x + 12
We have to show that, 2x – 3 is a factor of p(x).
i.e., `p(3/2) = 0`
Now, `p(3/2) = 2(3/2)^3 - 9(3/2)^2 + 3/2 + 12`
= `2 xx 27/8 - 9 xx 9/4 + 3/2 + 12`
= `27/4 - 81/4 + 3/2 + 12`
= `(27 - 81 + 6 + 48)/4`
= `(81 - 81)/4`
= 0
Hence, (2x – 3) is a factor of p(x).
APPEARS IN
संबंधित प्रश्न
Determine the following polynomial has (x + 1) a factor:
x3 + x2 + x + 1
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = `2x^2+kx+sqrt2`
Factorise:
3x2 – x – 4
Factorise:
x3 – 3x2 – 9x – 5
Find the factor of the polynomial given below.
3y2 – 2y – 1
Factorize the following polynomial.
(x – 5)2 – (5x – 25) – 24
Factorise:
x2 + 9x + 18
Factorise:
2x2 – 7x – 15
Factorise:
84 – 2r – 2r2
Factorise the following:
`8p^3 + 12/5 p^2 + 6/25 p + 1/125`
