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Question
Explain the formation of [CoF6]3Θ complex with respect to
- Hybridisation
- Magnetic properties
- Inner/outer complex
- Geometry
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Solution
Formation of [CoF6]3Θ ion:
- Oxidation state of central metal Co is +3.
- Valence shell electronic configuration of Co3⊕ is
- Six fluoride FΘ ligands, thus the number of vacant metal ion orbitals required for bonding with ligands would be six.
- Complex is high spin, which means the pairing of electrons will not take place prior to hybridisation. The electronic configuration would remain the same as in the free state shown above.
- Six orbitals available for hybridisation are one 4s, three 4p, two of 4d orbitals.
- Six metal orbitals after bonding with six FΘ ligands led to the sp3d2 hybridization.
- Six vacant sp3d2 hybrid orbitals of Co3+ overlap with six orbitals of fluoride forming Co-F coordinate bonds.
- Configuration after complex formation.
- The complex is octahedral and has four unpaired electrons and hence, is paramagnetic.
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\[\ce{[Ni(CN)4]^2-}\]
