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Question
On the basis of CFT predict the number of unpaired electrons in [CrF6]3-.
Options
1
2
3
4
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Solution
3
Explanation:
The[CrF6]3- complex contains a chromium ion with a +3 oxidation state. In this state, chromium has an electron configuration of 3d3, meaning there are three electrons in the d orbitals.
According to Crystal Field Theory for an octahedral complex, the d-orbitals split into two sets: t2g (lower energy) and eg (higher energy). Fluorine ligands are considered weak field ligands, and they cause a small energy gap between the t2g and eg orbitals.
A chromium ion with three d-electrons will fill the three t2g orbitals with one electron each to minimize repulsion, according to Hund's rule. As a result, all three d-electrons are unpaired.
Therefore, the [CrF6]3- complex has three unpaired electrons.
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\[\ce{[Ni(CN)4]^2-}\]
