Advertisements
Advertisements
प्रश्न
Explain the formation of [CoF6]3Θ complex with respect to
- Hybridisation
- Magnetic properties
- Inner/outer complex
- Geometry
Advertisements
उत्तर
Formation of [CoF6]3Θ ion:
- Oxidation state of central metal Co is +3.
- Valence shell electronic configuration of Co3⊕ is
- Six fluoride FΘ ligands, thus the number of vacant metal ion orbitals required for bonding with ligands would be six.
- Complex is high spin, which means the pairing of electrons will not take place prior to hybridisation. The electronic configuration would remain the same as in the free state shown above.
- Six orbitals available for hybridisation are one 4s, three 4p, two of 4d orbitals.
- Six metal orbitals after bonding with six FΘ ligands led to the sp3d2 hybridization.
- Six vacant sp3d2 hybrid orbitals of Co3+ overlap with six orbitals of fluoride forming Co-F coordinate bonds.
- Configuration after complex formation.
- The complex is octahedral and has four unpaired electrons and hence, is paramagnetic.
APPEARS IN
संबंधित प्रश्न
On the basis of CFT predict the number of unpaired electrons in [CrF6]3-.
Answer in brief.
[CoCl4]2− is a tetrahedral complex. Draw its box orbital diagram. State which orbitals participate in hybridization.
Answer in brief.
What are strong field and weak field ligands ? Give one example of each.
Answer in brief.
With the help of the crystal field, the energy-level diagram explains why the complex [Cr(en)3]3⊕ is coloured.
Answer the following question.
Give valence bond description for the bonding in the complex [VCl4]-. Draw box diagrams for the free metal ion. Which hybrid orbitals are used by the metal? State the number of unpaired electrons.
Explain, why [Co(NH3)6]3+ ion is low spin? Calculate number of unpaired electrons and write the geometry of [Co(NH3)6]3+.
Answer the following with respect to [CoF6]3– ion
- Type of hybridization
- Number of unpaired electrons
- Geometry of complex ion
- Magnetic property
Chlorophyll and haemoglobin are complexes of ____________ respectively.
The INCORRECT match for complex with its geometry is:
The number of unpaired electrons in the complex ion [NiCl4]2− is ____________.
Which one of the following complexes can exhibit geometrical isomerism?
What is the value of primary valence of Co in CoCl3?
What is the type of magnetic behavior and geometry respectively in Cuproammonium sulphate (Atomic number of Cu = 29)?
Describe the bonding in the tetrahedral complex Ni(CO)4 on the basis of valence bond theory. Give the orbital diagrams of metal atoms in free state and in the complex. Mention the number of unpaired electrons in the complex.
A compound forms hcp structure. What is the number of (a) octahedral voids, (b) tetrahedral voids, (c) total voids formed in 0.2 mol of the compound?
Give VBT description of the bonding in a square planar complex [Cu(NH3) 4]2+. Show orbital diagrams for free metal ion and metal ion in the complex. Which hybrid orbitals are used by metal for bonding? State magnetic nature of the complex.
Give a valence bond description of the bonding in the high spin complex [MnCl6]3− Include orbital diagram for the free metal ion and the metal ion in the complex. Indicate which hybrid orbitals the metal ion uses for bonding. Specify the number of unpaired electrons.
A compound forms a hep structure. Calculate the number of octahedral voids in 0.4 mol. (NA = 6.022 × 1023 )
Octahedral complex have ______ hybridisation.
Give the limitations of VBT.
Mention the type of hybridization in [Co(NH3)6]3+ complex.
Mention the number of unpaired electrons and geometry of the following complex:
\[\ce{[Ni(Cl)4]^{2-}}\]
Mention the number of unpaired electrons and geometry of the following complex:
\[\ce{[Ni(CN)4]^2-}\]
