Advertisements
Advertisements
Question
Expand (104)3
Sum
Advertisements
Solution
(104)3 = (100 + 4)3
Comparing (100 + 4)3 with (a + b)3 we have a = 100 and b = 4
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(100 + 4)3 = (100)3 + 3(100)2(4) + 3(100)(4)2 + 43
= 10,00,000 + 3(10000)4 + 300(16) + 64
= 10,00,000 + 1,20,000 + 4,800 + 64
= 11,24,864
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand.
(52)3
Expand.
`(x + 1/x)^3`
Expand.
`((5x)/y + y/(5x))^3`
If a2 + `1/a^2 = 47` and a ≠ 0 find :
- `a + 1/a`
- `a^3 + 1/a^3`
If 4x2 + y2 = a and xy = b, find the value of 2x + y.
If `3x - (1)/(3x) = 9`; find the value of `27x^3 - (1)/(27x^3)`.
If a + b = 5 and ab = 2, find a3 + b3.
If m - n = -2 and m3 - n3 = -26, find mn.
Expand: (41)3
Expand: `[x + 1/y]^3`
