Advertisements
Advertisements
Question
Expand (104)3
Sum
Advertisements
Solution
(104)3 = (100 + 4)3
Comparing (100 + 4)3 with (a + b)3 we have a = 100 and b = 4
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(100 + 4)3 = (100)3 + 3(100)2(4) + 3(100)(4)2 + 43
= 10,00,000 + 3(10000)4 + 300(16) + 64
= 10,00,000 + 1,20,000 + 4,800 + 64
= 11,24,864
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand.
(7x + 8y)3
Expand.
(52)3
If a + 2b = 5; then show that : a3 + 8b3 + 30ab = 125.
The sum of two numbers is 9 and their product is 20. Find the sum of their (i) Squares (ii) Cubes.
Find the cube of: `4"p" - (1)/"p"`
If `x + (1)/x = 5`, find the value of `x^2 + (1)/x^2, x^3 + (1)/x^3` and `x^4 + (1)/x^4`.
If `x^2 + (1)/x^2 = 18`; find : `x^3 - (1)/x^3`
If a + b + c = 0; then show that a3 + b3 + c3 = 3abc.
If a + 2b + c = 0; then show that a3 + 8b3 + c3 = 6abc
Expand: (x + 3)3.
