Advertisements
Advertisements
Question
If a ≠ 0 and `a - 1/a` = 3 ; find `a^2 + 1/a^2`
Sum
Advertisements
Solution
`a - 1/a = 3`
Squaring both sides,
⇒ `(a - 1/a)^2 = 3^2`
⇒ `a^2 + (1/a)^2 - 2(a) (1/a) = 9`
⇒ `a^2 + 1/a^2 - 2 = 9`
⇒ `a^2 + 1/a^2 = 11`
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Expand.
(7x + 8y)3
Use property to evaluate : 383 + (-26)3 + (-12)3
If 2x - 3y = 10 and xy = 16; find the value of 8x3 - 27y3.
Find the cube of: `3"a" + (1)/(3"a")`
If `3x - (1)/(3x) = 9`; find the value of `27x^3 - (1)/(27x^3)`.
If `"m"^2 + (1)/"m"^2 = 51`; find the value of `"m"^3 - (1)/"m"^3`
If p - q = -1 and pq = -12, find p3 - q3
Expand: (3x + 4y)3.
Expand: `[x + 1/y]^3`
(p + q)(p2 – pq + q2) is equal to _____________
