Advertisements
Advertisements
Question
Expand.
(7 + m)3
Sum
Advertisements
Solution
(7 + m)3
= (7)3 + 3 × (7)2 × (m) + 3 × (7) × (m)2 + (m)3 …[∵ (a + b)3 = a3 + 3a2b + 3ab2 + b3]
= 343 + 3(49)(m) + 3(7)(m2) + m3
= 343 + 147m + 21m2 + m3
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Find the cube of : `2a + 1/(2a)` ( a ≠ 0 )
Find the cube of: `( 3a - 1/a ) (a ≠ 0 )`
If a ≠ 0 and `a - 1/a` = 4; find: `(a^2 + 1/a^2)`
If `"a" - (1)/"a" = 7`, find `"a"^2 + (1)/"a"^2 , "a"^2 - (1)/"a"^2` and `"a"^3 - (1)/"a"^3`
If `x^2 + (1)/x^2 = 18`; find : `x^3 - (1)/x^3`
Simplify:
`("a" + 1/"a")^3 - ("a" - 1/"a")^3`
Expand: (41)3
Expand: `[x + 1/y]^3`
Find 27a3 + 64b3, if 3a + 4b = 10 and ab = 2
Expand (2a + 5)3
