English

Evaluate the following: sin 30° + cos 45° + tan 180° - Mathematics and Statistics

Advertisements
Advertisements

Question

Evaluate the following:

sin 30° + cos 45° + tan 180°

Sum
Advertisements

Solution

We know that,

sin 30° = `1/2`, cos 45° = `1/sqrt(2)`, tan 180° = 0

sin 30° + cos 45° + tan 180°

= `1/2 + 1/sqrt(2) + 0`

= `1/2 + 1/(sqrt2) xx sqrt2/sqrt2`           ...[Multiply numerator and denominator by `sqrt2`]

= `1/2 + sqrt2/2`

= `(1 + sqrt2)/2`

shaalaa.com
Fundamental Identities
  Is there an error in this question or solution?
Chapter 2: Trigonometry - 1 - EXERCISE 2.1 [Page 22]

RELATED QUESTIONS

Eliminate θ from the following: 

x = 3secθ , y = 4tanθ


Eliminate θ from the following : 

x = 6cosecθ, y = 8cotθ


Eliminate θ from the following :

x = 4cosθ − 5sinθ, y = 4sinθ + 5cosθ


Find sinθ such that 3cosθ + 4sinθ = 4


If cosecθ + cotθ = 5, then evaluate secθ.


Prove the following identities:

`(1 + tan^2 "A") + (1 + 1/tan^2"A") = 1/(sin^2 "A" - sin^4"A")`


Prove the following identities: 

(cos2A – 1) (cot2A + 1) = −1


Prove the following identities:

(sinθ + sec θ)2 + (cosθ + cosec θ)2 = (1 + cosecθ sec θ)2 


Prove the following identities:

`1/(sectheta + tantheta) - 1/costheta = 1/costheta - 1/(sectheta - tantheta)`


Prove the following identities:

`sintheta/(1 + costheta) + (1 + costheta)/sintheta` = 2cosecθ


Prove the following identities:

`cottheta/("cosec"  theta - 1) = ("cosec"  theta + 1)/cot theta`


Prove the following identities:

(sec A + cos A)(sec A − cos A) = tan2A + sin2A


Prove the following identities:

`(1 - sectheta + tan theta)/(1 + sec theta - tan theta) = (sectheta + tantheta - 1)/(sectheta + tantheta + 1)`


Select the correct option from the given alternatives:

If cosecθ + cotθ = `5/2`, then the value of tanθ is


Select the correct option from the given alternatives:

`1 - sin^2theta/(1 + costheta) + (1 + costheta)/sintheta - sintheta/(1 - costheta)` equals


Select the correct option from the given alternatives:

The value of tan1°.tan2°tan3°..... tan89° is equal to


Prove the following:  

sin2A cos2B + cos2A sin2B + cos2A cos2B + sin2A sin2B = 1


Prove the following:

`((1 + cot theta + tan theta)(sin theta - costheta)) /(sec^3theta - "cosec"^3theta)`= sin2θ cos2θ


Prove the following:

2 sec2θ – sec4θ – 2cosec2θ + cosec4θ = cot4θ – tan4θ


Prove the following:

2(sin6θ + cos6θ) – 3(sin4θ + cos4θ) + 1 = 0


Prove the following:

cos4θ − sin4θ +1= 2cos2θ


Prove the following:

sin4θ +2sin2θ . cos2θ = 1 − cos4θ


Prove the following:

`(sin^3theta + cos^3theta)/(sintheta + costheta) + (sin^3theta - cos^3theta)/(sintheta - costheta)` = 2


Prove the following:

(sinθ + cosecθ)2 + (cosθ + secθ)2 = tan2θ + cot2θ + 7


Prove the following:

sin6A + cos6A = 1 − 3sin2A + 3 sin4A


Prove the following:

`(tantheta + sectheta - 1)/(tantheta + sectheta + 1) = tantheta/(sec theta + 1)`


Prove the following:

`("cosec"theta + cottheta + 1)/(cottheta + "cosec" theta - 1) = cottheta/("cosec"theta - 1)`


Prove the following:

`("cosec"theta + cottheta - 1)/( "cosec"theta + cot theta + 1) =(1-sintheta)/costheta`


If θ lies in the first quadrant and 5 tan θ = 4, then `(5 sin θ - 3 cos θ)/(sin θ + 2 cos θ)` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×