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Evaluate the following: sin 30° + cos 45° + tan 180°

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प्रश्न

Evaluate the following:

sin 30° + cos 45° + tan 180°

योग
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उत्तर

We know that,

sin 30° = `1/2`, cos 45° = `1/sqrt(2)`, tan 180° = 0

sin 30° + cos 45° + tan 180°

= `1/2 + 1/sqrt(2) + 0`

= `1/2 + 1/(sqrt2) xx sqrt2/sqrt2`           ...[Multiply numerator and denominator by `sqrt2`]

= `1/2 + sqrt2/2`

= `(1 + sqrt2)/2`

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अध्याय 2: Trigonometry - 1 - EXERCISE 2.1 [पृष्ठ २२]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 2 Trigonometry - 1
EXERCISE 2.1 | Q 5) i) | पृष्ठ २२

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