हिंदी

Evaluate the following : sin 30° × cos 45° × tan 360°

Advertisements
Advertisements

प्रश्न

Evaluate the following : 

sin 30° × cos 45° × tan 360°

योग
Advertisements

उत्तर

We know that,

sin30° = `1/2, cos45^circ = 1/sqrt(2)`, tan 360° = 0

sin 30° × cos 45° × tan 360°

= `(1/2) xx (1/sqrt(2)) xx (0)` = 0

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Trigonometry - 1 - EXERCISE 2.1 [पृष्ठ २२]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 2 Trigonometry - 1
EXERCISE 2.1 | Q 5) iii) | पृष्ठ २२

संबंधित प्रश्न

Evaluate the following:

sin 30° + cos 45° + tan 180°


Evaluate the following : 

cosec 45° + cot 45° + tan 0°


Eliminate θ from the following :

x = 4cosθ − 5sinθ, y = 4sinθ + 5cosθ


Find the acute angle θ such that 2 cos2θ = 3 sin θ.


Find the acute angle θ such that 5tan2θ + 3 = 9secθ.


Find sinθ such that 3cosθ + 4sinθ = 4


If cosecθ + cotθ = 5, then evaluate secθ.


Prove the following identities:

`tan^3theta/(1 + tan^2theta) + cot^3theta/(1 + cot^2theta` = secθ cosecθ – 2sinθ cosθ


Prove the following identities:

`1/(sectheta + tantheta) - 1/costheta = 1/costheta - 1/(sectheta - tantheta)`


Prove the following identities:

`sintheta/(1 + costheta) + (1 + costheta)/sintheta` = 2cosecθ


Prove the following identity:

`tantheta/(sectheta - 1) = (sectheta + 1)/tantheta`


Prove the following identities:

(sec A + cos A)(sec A − cos A) = tan2A + sin2A


Prove the following identities:

`(1 - sectheta + tan theta)/(1 + sec theta - tan theta) = (sectheta + tantheta - 1)/(sectheta + tantheta + 1)`


Select the correct option from the given alternatives:

`1 - sin^2theta/(1 + costheta) + (1 + costheta)/sintheta - sintheta/(1 - costheta)` equals


Select the correct option from the given alternatives:

If cosecθ − cotθ = q, then the value of cot θ is


Select the correct option from the given alternatives:

The value of tan1°.tan2°tan3°..... tan89° is equal to


Prove the following:  

sin2A cos2B + cos2A sin2B + cos2A cos2B + sin2A sin2B = 1


Prove the following:

`(tan theta + 1/costheta)^2 + (tan theta - 1/costheta)^2 = 2((1 + sin^2theta)/(1 - sin^2theta))`


Prove the following:

2 sec2θ – sec4θ – 2cosec2θ + cosec4θ = cot4θ – tan4θ


Prove the following:

cos4θ − sin4θ +1= 2cos2θ


Prove the following:

sin4θ +2sin2θ . cos2θ = 1 − cos4θ


Prove the following:

tan2θ − sin2θ = sin4θ sec2θ


Prove the following:

(sinθ + cosecθ)2 + (cosθ + secθ)2 = tan2θ + cot2θ + 7


Prove the following:

sin8θ − cos8θ = (sin2θ − cos2θ) (1 − 2 sin2θ cos2θ)


Prove the following:

sin6A + cos6A = 1 − 3sin2A + 3 sin4A


Prove the following:

(1 + tanA · tanB)2 + (tanA − tanB)2 = sec2A · sec2B


Prove the following:

`("cosec"theta + cottheta + 1)/(cottheta + "cosec" theta - 1) = cottheta/("cosec"theta - 1)`


Prove the following:

`("cosec"theta + cottheta - 1)/( "cosec"theta + cot theta + 1) =(1-sintheta)/costheta`


Prove the following identity:

`(1 - sec theta + tan theta)/(1 + sec theta - tan theta) = (sec theta + tan theta - 1)/(sec theta + tan theta + 1)`


If θ lies in the first quadrant and 5 tan θ = 4, then `(5 sin θ - 3 cos θ)/(sin θ + 2 cos θ)` is equal to ______.


If 5 tan θ = 4. then `(5 sin θ − 3 cos θ)/(5 sin θ + 2 cos θ)` = ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×