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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Evaluate the following : sin 30° × cos 45° × tan 360°

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प्रश्न

Evaluate the following : 

sin 30° × cos 45° × tan 360°

बेरीज
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उत्तर

We know that,

sin30° = `1/2, cos45^circ = 1/sqrt(2)`, tan 360° = 0

sin 30° × cos 45° × tan 360°

= `(1/2) xx (1/sqrt(2)) xx (0)` = 0

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पाठ 2: Trigonometry - 1 - EXERCISE 2.1 [पृष्ठ २२]

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