मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Select the correct option from the given alternatives: The value of tan1°.tan2°tan3°..... tan89° is equal to - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Select the correct option from the given alternatives:

The value of tan1°.tan2°tan3°..... tan89° is equal to

पर्याय

  • – 1

  • 1

  • `pi/2`

  • 2

MCQ
Advertisements

उत्तर

1 

Explanation:

tan1° tan2° tan3° ...... tan89°

= (tan1° tan89°) (tan2° tan88°) .....(tan44° tan46°)tan45°

= (tan1° cot1°) (tan2° cot2°) ...(tan44° cot44°) . tan45° ....[∵ tan(90° − θ) = cot θ]

= 1 × 1 × 1 × ..... × 1 × tan45° = 1

shaalaa.com
Fundamental Identities
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Trigonometry - 1 - MISCELLANEOUS EXERCISE - 2 [पृष्ठ ३३]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 2 Trigonometry - 1
MISCELLANEOUS EXERCISE - 2 | Q I) 10) | पृष्ठ ३३

संबंधित प्रश्‍न

Evaluate the following : 

cosec 45° + cot 45° + tan 0°


Evaluate the following : 

sin 30° × cos 45° × tan 360°


Eliminate θ from the following: 

x = 3secθ , y = 4tanθ


Eliminate θ from the following : 

x = 6cosecθ, y = 8cotθ


Eliminate θ from the following :

x = 4cosθ − 5sinθ, y = 4sinθ + 5cosθ


Eliminate θ from the following :

x = 5 + 6cosecθ, y = 3 + 8cotθ


Eliminate θ from the following:

2x = 3 − 4 tan θ, 3y = 5 + 3 sec θ


Find the acute angle θ such that 2 cos2θ = 3 sin θ.


Find sinθ such that 3cosθ + 4sinθ = 4


If cotθ = `3/4` and π < θ < `(3pi)/2` then find the value of 4cosecθ + 5cosθ.


Prove the following identities: 

(cos2A – 1) (cot2A + 1) = −1


Prove the following identities:

`tan^3theta/(1 + tan^2theta) + cot^3theta/(1 + cot^2theta` = secθ cosecθ – 2sinθ cosθ


Prove the following identities:

`1/(sectheta + tantheta) - 1/costheta = 1/costheta - 1/(sectheta - tantheta)`


Prove the following identity:

`tantheta/(sectheta - 1) = (sectheta + 1)/tantheta`


Prove the following identities:

`cottheta/("cosec"  theta - 1) = ("cosec"  theta + 1)/cot theta`


Prove the following identities:

(sec A + cos A)(sec A − cos A) = tan2A + sin2A


Select the correct option from the given alternatives: 

`tan"A"/(1 + sec"A") + (1 + sec"A")/tan"A"` is equal to


Select the correct option from the given alternatives:

If cosecθ + cotθ = `5/2`, then the value of tanθ is


Select the correct option from the given alternatives:

`1 - sin^2theta/(1 + costheta) + (1 + costheta)/sintheta - sintheta/(1 - costheta)` equals


Prove the following:  

sin2A cos2B + cos2A sin2B + cos2A cos2B + sin2A sin2B = 1


Prove the following:

`((1 + cot theta + tan theta)(sin theta - costheta)) /(sec^3theta - "cosec"^3theta)`= sin2θ cos2θ


Prove the following:

`(tan theta + 1/costheta)^2 + (tan theta - 1/costheta)^2 = 2((1 + sin^2theta)/(1 - sin^2theta))`


Prove the following:

2(sin6θ + cos6θ) – 3(sin4θ + cos4θ) + 1 = 0


Prove the following:

cos4θ − sin4θ +1= 2cos2θ


Prove the following:

`(sin^3theta + cos^3theta)/(sintheta + costheta) + (sin^3theta - cos^3theta)/(sintheta - costheta)` = 2


Prove the following:

(sinθ + cosecθ)2 + (cosθ + secθ)2 = tan2θ + cot2θ + 7


Prove the following:

sin8θ − cos8θ = (sin2θ − cos2θ) (1 − 2 sin2θ cos2θ)


Prove the following:

(1 + tanA · tanB)2 + (tanA − tanB)2 = sec2A · sec2B


Prove the following:

`(1 + cottheta  +  "cosec" theta)/(1 - cottheta  +  "cosec" theta) = ("cosec" theta  + cottheta - 1)/(cottheta - "cosec"theta + 1)`


Prove the following identity:

`(1 - sec theta + tan theta)/(1 + sec theta - tan theta) = (sec theta + tan theta - 1)/(sec theta + tan theta + 1)`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×