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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Prove the following: tanθ+secθ-1tanθ+secθ+1=tanθsecθ+1

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प्रश्न

Prove the following:

`(tantheta + sectheta - 1)/(tantheta + sectheta + 1) = tantheta/(sec theta + 1)`

बेरीज
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उत्तर १

We know that,

tan2θ = sec2θ – 1

∴ tanθ.tanθ = (secθ + 1)(secθ – 1)

∴ `tantheta/(sec theta + 1) = (sectheta - 1)/tantheta`

By the theorem on equal ratios, we get

`tantheta/(sec theta + 1) = (sectheta - 1)/tantheta = (tantheta + sectheta - 1)/(tantheta + 1 + tantheta)`

∴ `(tantheta + sectheta - 1)/(tantheta + sectheta + 1) = tantheta/(sec theta + 1)`

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उत्तर २

`(tantheta + sectheta - 1)/(tantheta + sectheta + 1) = tantheta/(sec theta + 1)`

(tanθ + secθ − 1)(secθ + 1) = tanθ (tanθ + secθ + 1)

tanθ secθ + tanθ + sec2θ − 1

tan2θ + tanθ secθ + tanθ

tanθ secθ + tanθ + sec2θ − 1 = tan2θ + tanθ secθ + tanθ

`(tantheta + sectheta - 1)/(tantheta + sectheta + 1) = tantheta/(sec theta + 1)`

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Trigonometry - 1 - MISCELLANEOUS EXERCISE - 2 [पृष्ठ ३४]

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बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 11 Maharashtra State Board
पाठ 2 Trigonometry - 1
MISCELLANEOUS EXERCISE - 2 | Q 10) xvi) | पृष्ठ ३४

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