मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Prove the following identities: coseccoseccotθcosec θ-1=cosec θ+1cotθ

Advertisements
Advertisements

प्रश्न

Prove the following identities:

`cottheta/("cosec"  theta - 1) = ("cosec"  theta + 1)/cot theta`

बेरीज
Advertisements

उत्तर

L.H.S. = `cottheta/("cosec"  theta - 1)`

= `cottheta/("cosec" theta - 1) xx ("cosec" theta + 1)/("cosec" theta + 1)`

= `(cottheta("cosec" + 1))/("cosec"^2theta - 1)`

= `(cot theta("cosec" theta + 1))/cot^2 theta  ...[(because 1 + cot^2theta = "cosec"^2theta),(therefore "cosec"^2theta - 1 = cot^2theta)]`

= `("cosec" theta + 1)/cot theta`

= R.H.S.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Trigonometry - 1 - EXERCISE 2.2 [पृष्ठ ३१]

APPEARS IN

संबंधित प्रश्‍न

Evaluate the following:

sin 30° + cos 45° + tan 180°


Evaluate the following : 

cosec 45° + cot 45° + tan 0°


Evaluate the following : 

sin 30° × cos 45° × tan 360°


Eliminate θ from the following: 

x = 3secθ , y = 4tanθ


Eliminate θ from the following : 

x = 6cosecθ, y = 8cotθ


Find the acute angle θ such that 5tan2θ + 3 = 9secθ.


Find sinθ such that 3cosθ + 4sinθ = 4


If cosecθ + cotθ = 5, then evaluate secθ.


Prove the following identities:

`(1 + tan^2 "A") + (1 + 1/tan^2"A") = 1/(sin^2 "A" - sin^4"A")`


Prove the following identities: 

(cos2A – 1) (cot2A + 1) = −1


Prove the following identities:

(sinθ + sec θ)2 + (cosθ + cosec θ)2 = (1 + cosecθ sec θ)2 


Prove the following identities:

`tan^3theta/(1 + tan^2theta) + cot^3theta/(1 + cot^2theta` = secθ cosecθ – 2sinθ cosθ


Prove the following identities:

`sintheta/(1 + costheta) + (1 + costheta)/sintheta` = 2cosecθ


Prove the following identity:

1 + 3cosec2θ cot2θ + cot6θ = cosec6θ


Prove the following identities:

`(1 - sectheta + tan theta)/(1 + sec theta - tan theta) = (sectheta + tantheta - 1)/(sectheta + tantheta + 1)`


Select the correct option from the given alternatives:

If θ = 60°, then `(1 + tan^2theta)/(2tantheta)` is equal to


Select the correct option from the given alternatives:

`1 - sin^2theta/(1 + costheta) + (1 + costheta)/sintheta - sintheta/(1 - costheta)` equals


Select the correct option from the given alternatives:

The value of tan1°.tan2°tan3°..... tan89° is equal to


Prove the following:  

sin2A cos2B + cos2A sin2B + cos2A cos2B + sin2A sin2B = 1


Prove the following:

cos4θ − sin4θ +1= 2cos2θ


Prove the following:

`(sin^3theta + cos^3theta)/(sintheta + costheta) + (sin^3theta - cos^3theta)/(sintheta - costheta)` = 2


Prove the following:

tan2θ − sin2θ = sin4θ sec2θ


Prove the following:

sin8θ − cos8θ = (sin2θ − cos2θ) (1 − 2 sin2θ cos2θ)


Prove the following:

sin6A + cos6A = 1 − 3sin2A + 3 sin4A


Prove the following:

(1 + tanA · tanB)2 + (tanA − tanB)2 = sec2A · sec2B


Prove the following:

`("cosec"theta + cottheta + 1)/(cottheta + "cosec" theta - 1) = cottheta/("cosec"theta - 1)`


Prove the following:

`("cosec"theta + cottheta - 1)/( "cosec"theta + cot theta + 1) =(1-sintheta)/costheta`


Prove the following identity:

`(1 - sec theta + tan theta)/(1 + sec theta - tan theta) = (sec theta + tan theta - 1)/(sec theta + tan theta + 1)`


If θ lies in the first quadrant and 5 tan θ = 4, then `(5 sin θ - 3 cos θ)/(sin θ + 2 cos θ)` is equal to ______.


If 5 tan θ = 4. then `(5 sin θ − 3 cos θ)/(5 sin θ + 2 cos θ)` = ______. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×