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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Prove the following: sin4θ +2sin2θ . cos2θ = 1 − cos4θ

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प्रश्न

Prove the following:

sin4θ +2sin2θ . cos2θ = 1 − cos4θ

बेरीज
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उत्तर

L.H.S. =sin4θ +2sin2θ . cos2θ

= sin2θ(sin2θ + 2cos2θ)

= (sin2θ) (sin2θ + cos2θ + cos2θ)

= (1 – cos2θ) (1 + cos2θ)

= 1 – cos4θ

= R.H.S.

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पाठ 2: Trigonometry - 1 - MISCELLANEOUS EXERCISE - 2 [पृष्ठ ३४]

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बालभारती Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
पाठ 2 Trigonometry - 1
MISCELLANEOUS EXERCISE - 2 | Q 10) viii) | पृष्ठ ३४

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