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Prove the following identities: 1secθ+tanθ-1cosθ=1cosθ-1secθ-tanθ - Mathematics and Statistics

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Question

Prove the following identities:

`1/(sectheta + tantheta) - 1/costheta = 1/costheta - 1/(sectheta - tantheta)`

Sum
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Solution

We have to prove that,

`1/(sectheta + tantheta) - 1/costheta = 1/costheta - 1/(sectheta - tantheta)`

`1/(sectheta + tantheta) + 1/(sectheta - tantheta) = 1/costheta + 1/costheta`

`1/(sectheta + tantheta) + 1/(sec theta - tan theta) = 2/costheta`

L.H.S. = `1/(sectheta + tantheta) + 1/(sec theta - tan theta)`

= `(sectheta -  tantheta + sectheta + tantheta)/((sectheta + tantheta)(sectheta - tantheta))`

= `(2sectheta)/(sec^2theta - tan^2theta)` .....[a2 − b2 = (a + b) (a − b)]

= `(2secθ)/1`  ...`[(because sec^2theta = 1 + tan^2theta),(therefore sec^2 theta - tan^2theta = 1)]`

= 2secθ

= `2 xx 1/(cosθ)`

= `2/costheta`

= R.H.S.

Hence proved.

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Fundamental Identities
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Chapter 2: Trigonometry - 1 - EXERCISE 2.2 [Page 31]

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