English

Evaluate the following : cosec 45° + cot 45° + tan 0° - Mathematics and Statistics

Advertisements
Advertisements

Question

Evaluate the following : 

cosec 45° + cot 45° + tan 0°

Sum
Advertisements

Solution

We know that,

cosec 45° = `sqrt(2)`, cot 45° = 1, tan 0° = 0

cosec 45° + cot 45° + tan 0°

= `sqrt(2) + 1 + 0`

= `sqrt(2) + 1`

shaalaa.com
Important Identities and Standard Results
  Is there an error in this question or solution?
Chapter 2: Trigonometry - 1 - EXERCISE 2.1 [Page 22]

RELATED QUESTIONS

Evaluate the following:

sin 30° + cos 45° + tan 180°


Evaluate the following : 

sin 30° × cos 45° × tan 360°


Eliminate θ from the following :

x = 4cosθ − 5sinθ, y = 4sinθ + 5cosθ


Eliminate θ from the following :

x = 5 + 6cosecθ, y = 3 + 8cotθ


Eliminate θ from the following:

2x = 3 − 4 tan θ, 3y = 5 + 3 sec θ


Find the acute angle θ such that 5tan2θ + 3 = 9secθ.


If cosecθ + cotθ = 5, then evaluate secθ.


Prove the following identities:

`(1 + tan^2 "A") + (1 + 1/tan^2"A") = 1/(sin^2 "A" - sin^4"A")`


Prove the following identities: 

(cos2A – 1) (cot2A + 1) = −1


Prove the following identities:

(1 + cot θ – cosec θ)(1 + tan θ + sec θ) = 2


Prove the following identities:

`tan^3theta/(1 + tan^2theta) + cot^3theta/(1 + cot^2theta` = secθ cosecθ – 2sinθ cosθ


Prove the following identity:

1 + 3cosec2θ cot2θ + cot6θ = cosec6θ


Prove the following identities:

`(1 - sectheta + tan theta)/(1 + sec theta - tan theta) = (sectheta + tantheta - 1)/(sectheta + tantheta + 1)`


Select the correct option from the given alternatives: 

`tan"A"/(1 + sec"A") + (1 + sec"A")/tan"A"` is equal to


Select the correct option from the given alternatives:

If θ = 60°, then `(1 + tan^2theta)/(2tantheta)` is equal to


Select the correct option from the given alternatives:

`1 - sin^2theta/(1 + costheta) + (1 + costheta)/sintheta - sintheta/(1 - costheta)` equals


Select the correct option from the given alternatives:

If cosecθ − cotθ = q, then the value of cot θ is


Select the correct option from the given alternatives:

The value of tan1°.tan2°tan3°..... tan89° is equal to


Prove the following:

`((1 + cot theta + tan theta)(sin theta - costheta)) /(sec^3theta - "cosec"^3theta)`= sin2θ cos2θ


Prove the following:

`(tan theta + 1/costheta)^2 + (tan theta - 1/costheta)^2 = 2((1 + sin^2theta)/(1 - sin^2theta))`


Prove the following:

2 sec2θ – sec4θ – 2cosec2θ + cosec4θ = cot4θ – tan4θ


Prove the following:

sin4θ + cos4θ = 1 – 2 sin2θ cos2θ


Prove the following:

2(sin6θ + cos6θ) – 3(sin4θ + cos4θ) + 1 = 0


Prove the following:

cos4θ − sin4θ +1= 2cos2θ


Prove the following:

`(sin^3theta + cos^3theta)/(sintheta + costheta) + (sin^3theta - cos^3theta)/(sintheta - costheta)` = 2


Prove the following:

tan2θ − sin2θ = sin4θ sec2θ


Prove the following:

sin8θ − cos8θ = (sin2θ − cos2θ) (1 − 2 sin2θ cos2θ)


Prove the following:

`(1 + cottheta  +  "cosec" theta)/(1 - cottheta  +  "cosec" theta) = ("cosec" theta  + cottheta - 1)/(cottheta - "cosec"theta + 1)`


Prove the following:

`(tantheta + sectheta - 1)/(tantheta + sectheta + 1) = tantheta/(sec theta + 1)`


Prove the following:

`("cosec"theta + cottheta + 1)/(cottheta + "cosec" theta - 1) = cottheta/("cosec"theta - 1)`


Prove the following identity:

`(1 - sec theta + tan theta)/(1 + sec theta - tan theta) = (sec theta + tan theta - 1)/(sec theta + tan theta + 1)`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×