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Select the correct option from the given alternatives: tanA1+secA+1+secAtanA is equal to

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Question

Select the correct option from the given alternatives: 

`tan"A"/(1 + sec"A") + (1 + sec"A")/tan"A"` is equal to

Options

  • 2cosecA

  • 2secA

  • 2sinA

  • 2cosA

MCQ
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Solution

2cosec A

Explanation:

`tan"A"/(1 + sec"A") + (1 + sec"A")/tan"A"`

= `(tan^2"A"+1+sec^2"A"+2sec"A")/((1+sec"A")tan"A")`

= `(sec^2"A"+sec^2"A"+2sec"A")/((1+sec"A")tan"A")` ......[∵ 1 + tan2A = sec2A]

= `(2sec"A"(sec"A"+1))/((1+sec"A")tan"A")=(2sec"A")/(tan"A")`

= `2/(sin"A")` = 2cosecA

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Chapter 2: Trigonometry - 1 - MISCELLANEOUS EXERCISE - 2 [Page 32]

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