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Question
Evaluate the following :
Find the limit of the function, if it exists, at x = 1
f(x) = `{(7 - 4x, "for", x < 1),(x^2 + 2, "for", x ≥ 1):}`
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Solution
f(x) = `{(7 - 4x, "for", x < 1),(x^2 + 2, "for", x ≥ 1):}`
`lim_(x -> 1^-)` f(x) = `lim_(x -> 1)` (7 − 4x)
= 7 – 4(1)
= 3
`lim_(x -> 1^+)` f(x) = `lim_(x -> 1)` (x2 + 2)
= (1)2 + 2
= 3
∴ `lim_(x -> 1^-)` f(x) = `lim_(x -> 1^+)` f(x)
∴ `lim_(x -> 1^+)` f(x) exists and is equal to 3.
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