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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Evaluate the following limits: limx→01+sinx-1-sinxtanx - Mathematics

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Question

Evaluate the following limits:

`lim_(x -> 0) (sqrt(1 + sinx) - sqrt(1 - sinx))/tanx`

Sum
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Solution

`lim_(x -> 0) (sqrt(1 + sinx) - sqrt(1 - sinx))/tanx =  lim_(x -> 0) ((sqrt(1 + sinx)  sqrt(1 - sinx))(sqrt(1 + sinx) + sqrt(1 -  sinx)))/(tanx(sqrt(1 - sinx) + sqrt(1 - sinx))`

= `lim_(x -> 0) ((1 + sinx) - (1 -sinx))/(sinx/cosx (sqrt(1 +  sinx) + sqrt(1 -  sin))`

= `lim_(x -> 0) (cosx[1 + sinx - 1 + sinx])/(sinx(sqrt(1 + sinx) + sqrt(1 - sinx))`

= `lim_(x -> 0) (cosx xx 2sinx)/(sinx(sqrt(1 + sinx) + sqrt(1 - sinx))`

= `2 lim_(x -> 0) cosx/((sqrt(1 + sinx) + sqrt(1 -  sinx))`

= `2 x (cos 0)/((sqrt(1 +  sin0) + sqrt(1 - sin))`

= `(2 xx 1)/((sqrt(1 + 0) + sqrt(1 - 0))`

= `2/(1 +1)`

= `2/2`

`lim_(x -> 0) (sqrt(1 + sinx) - sqrt(1 - sinx))/tanx` = 1

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Chapter 9: Differential Calculus - Limits and Continuity - Exercise 9.4 [Page 118]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 9 Differential Calculus - Limits and Continuity
Exercise 9.4 | Q 23 | Page 118

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