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Differentiate the following w.r.t.x : y = 7x+x7-23xx-logx+77 - Mathematics and Statistics

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Question

Differentiate the following w.r.t.x :

y = `7^x + x^7 - 2/3 xsqrt(x) - logx + 7^7`

Sum
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Solution

y = `7^x + x^7 - 2/3 xsqrt(x) - logx + 7^7`

Differentiating w.r.t. x, we get

`("d"y)/("d"x) = "d"/("d"x) (7^x + x^7 - 2/3 xsqrt(x) - log x + 7^7)`

∴ `("d"y)/("d"x) = "d"/("d"x) (7^x) + "d"/("d"x) (x^7) - 2/3 "d"/("d"x) (x^(3/2)) - "d"/("d"x) (logx) + "d"/("d"x) 7^7`

= `7^x log 7 + 7x^6 - 2/3 xx 3/2 x^(3/2 - 1) - 1/x + 0`

= `7^x log 7 + 7x^6 - x^(1/2) - 1/x`

= `7^x log 7 + 7x^6 - sqrt(x) - 1/x`

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Rules of Differentiation (Without Proof)
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Chapter 9: Differentiation - Exercise 9.2 [Page 192]

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