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Question
Find `dy/dx` if y = (1 – x) (2 – x)
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Solution
y = (1 – x) (2 – x)
= 2 – 3x + x2
Differentiating w.r.t. x, we get
`dy/dx=d/dx(2 - 3x + x^2)`
= `d/dx(2) - 3d/dx(x) + d/dx(x^2)`
= 0 – 3(1) + 2x
= –3 + 2x
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