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Question
Find `dy/dx if y=(sqrtx+1)^2`
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Solution
`y=(sqrtx+1)^2`
∴ `y = x + 2 sqrtx + 1`
Differentiating w.r.t. x, we get
`dy/dx=d/dx(x+2sqrtx+1)`
=`d/dx(x)+2d/dx(sqrtx)+d/dx(1)`
= `1+2(1/(2sqrtx))+0`
`dy/dx=1+1/sqrtx`
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