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D Y D X = Sin 2 Y

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Question

\[\frac{dy}{dx} = \sin^2 y\]
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Solution

We have,
\[\frac{dy}{dx} = \sin^2 y\]
\[ \Rightarrow \frac{dx}{dy} = \frac{1}{\sin^2 y}\]
\[ \Rightarrow dx = {cosec}^2 y dy\]
Integrating both sides, we get
\[\int dx = \int {cosec}^2 y dy\]
\[ \Rightarrow x = - \cot y + C\]
\[ \Rightarrow x + \cot y = C\]
\[\text{ Hence, }x + \cot y = \text{ C is the required solution }.\]

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Chapter 21: Differential Equations - Exercise 22.06 [Page 38]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 21 Differential Equations
Exercise 22.06 | Q 3 | Page 38

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