Question

Solve the following differential equation:
\[y e^\frac{x}{y} dx = \left( x e^\frac{x}{y} + y^2 \right)dy, y \neq 0\]

 

Answer 1

\[y e^\frac{x}{y} dx = \left( x e^\frac{x}{y} + y^2 \right)dy\]
\[ \Rightarrow y e^\frac{x}{y} dx = x e^\frac{x}{y} dy + y^2 dy\]
\[ \Rightarrow y e^\frac{x}{y} dx - x e^\frac{x}{y} dy = y^2 dy\]
\[ \Rightarrow \left( ydx - xdy \right) e^\frac{x}{y} = y^2 dy\]
\[ \Rightarrow \frac{\left( ydx - xdy \right)}{y^2} e^\frac{x}{y} = dy\]
\[ \Rightarrow e^\frac{x}{y} d\left( \frac{x}{y} \right) = dy\]
\[ \Rightarrow \int e^\frac{x}{y} d\left( \frac{x}{y} \right) = \int dy\]
\[ \Rightarrow e^\frac{x}{y} = y + C\]