हिंदी

D Y D X = Sin 2 Y

Advertisements
Advertisements

प्रश्न

\[\frac{dy}{dx} = \sin^2 y\]
Advertisements

उत्तर

We have,
\[\frac{dy}{dx} = \sin^2 y\]
\[ \Rightarrow \frac{dx}{dy} = \frac{1}{\sin^2 y}\]
\[ \Rightarrow dx = {cosec}^2 y dy\]
Integrating both sides, we get
\[\int dx = \int {cosec}^2 y dy\]
\[ \Rightarrow x = - \cot y + C\]
\[ \Rightarrow x + \cot y = C\]
\[\text{ Hence, }x + \cot y = \text{ C is the required solution }.\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 21: Differential Equations - Exercise 22.06 [पृष्ठ ३८]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 21 Differential Equations
Exercise 22.06 | Q 3 | पृष्ठ ३८

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Show that the function y = A cos 2x − B sin 2x is a solution of the differential equation \[\frac{d^2 y}{d x^2} + 4y = 0\].


Hence, the given function is the solution to the given differential equation. \[\frac{c - x}{1 + cx}\] is a solution of the differential equation \[(1+x^2)\frac{dy}{dx}+(1+y^2)=0\].


Verify that y2 = 4a (x + a) is a solution of the differential equations
\[y\left\{ 1 - \left( \frac{dy}{dx} \right)^2 \right\} = 2x\frac{dy}{dx}\]


For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x^3 \frac{d^2 y}{d x^2} = 1\]
\[y = ax + b + \frac{1}{2x}\]

Differential equation \[\frac{dy}{dx} = y, y\left( 0 \right) = 1\]
Function y = ex


\[\left( x^2 + 1 \right)\frac{dy}{dx} = 1\]

\[\frac{dy}{dx} = x^5 \tan^{- 1} \left( x^3 \right)\]

C' (x) = 2 + 0.15 x ; C(0) = 100


xy (y + 1) dy = (x2 + 1) dx


Solve the differential equation \[\frac{dy}{dx} = e^{x + y} + x^2 e^y\].

(ey + 1) cos x dx + ey sin x dy = 0


\[\sqrt{1 + x^2 + y^2 + x^2 y^2} + xy\frac{dy}{dx} = 0\]

\[\cos x \cos y\frac{dy}{dx} = - \sin x \sin y\]

\[\frac{dy}{dx} = y \sin 2x, y\left( 0 \right) = 1\]

\[\cos y\frac{dy}{dx} = e^x , y\left( 0 \right) = \frac{\pi}{2}\]

Solve the differential equation \[\left( 1 + x^2 \right)\frac{dy}{dx} + \left( 1 + y^2 \right) = 0\], given that y = 1, when x = 0.


Find the particular solution of edy/dx = x + 1, given that y = 3, when x = 0.


If y(x) is a solution of the different equation \[\left( \frac{2 + \sin x}{1 + y} \right)\frac{dy}{dx} = - \cos x\] and y(0) = 1, then find the value of y(π/2).


\[\frac{dy}{dx} = \tan\left( x + y \right)\]

\[\frac{dy}{dx} = \frac{y - x}{y + x}\]

Solve the following differential equations:
\[\frac{dy}{dx} = \frac{y}{x}\left\{ \log y - \log x + 1 \right\}\]


Find the equation of the curve which passes through the origin and has the slope x + 3y− 1 at any point (x, y) on it.


Which of the following is the integrating factor of (x log x) \[\frac{dy}{dx} + y\] = 2 log x?


Form the differential equation representing the family of parabolas having vertex at origin and axis along positive direction of x-axis.


If a + ib = `("x" + "iy")/("x" - "iy"),` prove that `"a"^2 +"b"^2 = 1` and `"b"/"a" = (2"xy")/("x"^2 - "y"^2)`


Determine the order and degree of the following differential equations.

Solution D.E.
y = 1 − logx `x^2(d^2y)/dx^2 = 1`

Determine the order and degree of the following differential equations.

Solution D.E
y = aex + be−x `(d^2y)/dx^2= 1`

Solve the following differential equation.

y2 dx + (xy + x2 ) dy = 0


The differential equation of `y = k_1e^x+ k_2 e^-x` is ______.


Choose the correct alternative.

The solution of `x dy/dx = y` log y is


Select and write the correct alternative from the given option for the question

Bacterial increases at the rate proportional to the number present. If original number M doubles in 3 hours, then number of bacteria will be 4M in


Solve the differential equation sec2y tan x dy + sec2x tan y dx = 0


Solve the following differential equation y log y = `(log  y - x) ("d"y)/("d"x)`


Choose the correct alternative:

Solution of the equation `x("d"y)/("d"x)` = y log y is


Solve the following differential equation `("d"y)/("d"x)` = x2y + y


Solve: ydx – xdy = x2ydx.


Solve the differential equation `"dy"/"dx"` = 1 + x + y2 + xy2, when y = 0, x = 0.


The differential equation (1 + y2)x dx – (1 + x2)y dy = 0 represents a family of:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×