Advertisements
Advertisements
Question
Construct an isosceles triangle ABC such that AB = 6 cm, BC = AC = 4 cm. Bisect ∠C internally and mark a point P on this bisector such that CP = 5 cm. Find the points Q and R which are 5 cm from P and also 5 cm from the line AB.
Advertisements
Solution
Steps of construction:
- Draw a line segment AB = 6 cm.
- With centers A and B and radius 4 cm, draw two arcs which intersect each other at C.
- Join CA and CB.
- Draw the angle bisector of angle C and cut off CP = 5 cm.
- A line m is drawn parallel to AB at a distance of 5 cm.
- P as centre and radius 5 cm, draw arcs which intersect the line m at Q and R.
- Join PQ, PR and AQ.
Q and R are the required points.
APPEARS IN
RELATED QUESTIONS
On a graph paper, draw the line x = 6. Now, on the same graph paper, draw the locus of the point which moves in such a way that its distantce from the given line is always equal to 3 units
O is a fixed point. Point P moves along a fixed line AB. Q is a point on OP produced such that OP = PQ. Prove that the locus of point Q is a line parallel to AB.
State the locus of a point in a rhombus ABCD, which is equidistant
- from AB and AD;
- from the vertices A and C.
In the given figure ABC is a triangle. CP bisects angle ACB and MN is perpendicular bisector of BC. MN cuts CP at Q. Prove Q is equidistant from B and C, and also that Q is equidistant from BC and AC.
In given figure 1 ABCD is an arrowhead. AB = AD and BC = CD. Prove th at AC produced bisects BD at right angles at the point M
Draw and describe the lorus in the following cases:
The locus of points at a distance of 4 cm from a fixed line.
Describe completely the locus of a point in the following case:
Centre of a ball, rolling along a straight line on a level floor.
State and draw the locus of a swimmer maintaining the same distance from a lighthouse.
State and draw the locus of a point equidistant from two given parallel lines.
Ruler and compass only may be used in this question. All construction lines and arcs must be clearly shown, and be of sufficient length and clarity to permit assessment.
(i) Construct Δ ABC, in which BC = 8 cm, AB = 5 cm, ∠ ABC = 60°.
(ii) Construct the locus of point inside the triangle which are equidistant from BA and BC.
(iii) Construct the locus of points inside the triangle which are equidistant from B and C.
(iv) Mark as P, the point which is equidistant from AB, BC and also equidistant from B and C.
(v) Measure and record the length of PB.
