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Consider the following molecular formulae of carbon compounds: (i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H8 (a) Which one of these compounds belongs to homologous series of alcohols?

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Question

Consider the following molecular formulae of carbon compounds:

(i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H8 

  1. Which one of these compounds belongs to homologous series of alcohols?
  2. Identify the compound having triple bond between carbon-carbon atoms.
  3. Write the molecular formula of the first member of the homologous series to which CH3COOH belongs.
  4. Write the general formula of the series to which the compound C4H8 belongs.
Answer in Brief
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Solution

  1. Methanol (CH3OH) belongs to homologous series of alcohols.
  2. C3H4 has triple bond between carbon atoms.
  3. Methanoic acid (HCOOH)
  4. General formula of C4H8 is CnH2n.
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2021-2022 (March) Outside Delhi Set 2

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