Question

Consider the following molecular formulae of carbon compounds:

(i) CH₃COOH (ii) CH₃OH (iii) C₂H₆ (iv) C₃H₄ (v) C₄H₈ 

1. Which one of these compounds belongs to homologous series of alcohols?
2. Identify the compound having triple bond between carbon-carbon atoms.
3. Write the molecular formula of the first member of the homologous series to which CH₃COOH belongs.
4. Write the general formula of the series to which the compound C₄H₈ belongs.

Answer 1

1. Methanol (CH₃OH) belongs to homologous series of alcohols.
2. C₃H₄ has triple bond between carbon atoms.
3. Methanoic acid (HCOOH)
4. General formula of C₄H₈ is C_nH_2n.