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Consider the following molecular formulae of carbon compounds: (i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H8 (a) Which one of these compounds belongs to homologous series of alcohols? - Science

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प्रश्न

Consider the following molecular formulae of carbon compounds:

(i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H

  1. Which one of these compounds belongs to homologous series of alcohols?
  2. Identify the compound having triple bond between carbon-carbon atoms.
  3. Write the molecular formula of the first member of the homologous series to which CH3COOH belongs.
  4. Write the general formula of the series to which the compound C4H8 belongs.
संक्षेप में उत्तर
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उत्तर

  1. Methanol (CH3OH) belongs to homologous series of alcohols.
  2. C3H4 has triple bond between carbon atoms.
  3. Methanoic acid (HCOOH)
  4. General formula of C4H8 is CnH2n.
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Consider the carbon compounds having following molecular formula:

(i) C2H2 (ii) C2H5 (iii) C3H7OH (iv) C2H6COOH (v) CH3CHO

  1. Identify which one of the above compounds, is a member of aldehyde series.
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  3. Which one of the above compounds has triple bonds between carbon-carbon atoms?
  4. Write the molecular formula of the first member of the homologous series to which the compound C3H7OH belongs.

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