हिंदी

Consider the following molecular formulae of carbon compounds: (i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H8 (a) Which one of these compounds belongs to homologous series of alcohols?

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प्रश्न

Consider the following molecular formulae of carbon compounds:

(i) CH3COOH (ii) CH3OH (iii) C2H6 (iv) C3H4 (v) C4H

  1. Which one of these compounds belongs to homologous series of alcohols?
  2. Identify the compound having triple bond between carbon-carbon atoms.
  3. Write the molecular formula of the first member of the homologous series to which CH3COOH belongs.
  4. Write the general formula of the series to which the compound C4H8 belongs.
संक्षेप में उत्तर
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उत्तर

  1. Methanol (CH3OH) belongs to homologous series of alcohols.
  2. C3H4 has triple bond between carbon atoms.
  3. Methanoic acid (HCOOH)
  4. General formula of C4H8 is CnH2n.
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2021-2022 (March) Outside Delhi Set 2

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Consider the carbon compounds having following molecular formula:

(i) C3H6 (ii) C3H8 (iii) C4H6 (iv) C6H6 (v) C6H12

  1. State the number of double covalent bonds present in C3H8.
  2. Write the formula of first member of the homologous series to which the carbon compound C4H6 belongs.
  3. Which one of the above compounds forms a ring structure of carbon atoms?
  4. Identify, which of the above compounds, is a member of alkane series.

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