Question

Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

Answer 1

Given Charge, Q = 96000C

Time, t = 1hr = 60 x 60 = 3600s

Potential difference, V= 50volts

Now we know that H = VIt

So we have to calculate I first

As I = `Q/t`

∴ I = `96000/3600`

= `80/3A`

H = V × I × t

By substituting the values,

`50 xx 80/3 xx 60 xx 60`

= 4.8 × 106 J

Therefore, the heat generated is 4.8 × 10⁶ J.