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Question
Calculate the shortest wavelength of the spectral lines emitted in Balmer series.
[Given Rydberg constant, R = 107 m–1]
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Solution
For Blamer series, wavelength is given as
`1/lambda=R(1/2^2-1/n^2)`
For shortest wavelength, n = ∞
`:.1/lambda=R(1/2^2-0)=R/4`
`=>lambda=4/R=4xx10^-7 m`
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