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Question
Which expression is de Broglie’s relation for wavelength?
Options
\[\lambda=\frac{h}{2\pi p}\]
\[\lambda=hp\]
\[\lambda=\frac{p}{h}\]
\[\lambda=\frac{h}{p}\]
MCQ
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Solution
De Broglie’s relation is \[\lambda=\frac{h}{p}\]. Here, \[p\] is the magnitude of the electron’s momentum.
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