Advertisements
Advertisements
प्रश्न
Calculate the shortest wavelength of the spectral lines emitted in Balmer series.
[Given Rydberg constant, R = 107 m–1]
Advertisements
उत्तर
For Blamer series, wavelength is given as
`1/lambda=R(1/2^2-1/n^2)`
For shortest wavelength, n = ∞
`:.1/lambda=R(1/2^2-0)=R/4`
`=>lambda=4/R=4xx10^-7 m`
APPEARS IN
संबंधित प्रश्न
How does one explain, using de Broglie hypothesis, Bohr's second postulate of quantization of orbital angular momentum?
A uniform magnetic field B exist in a region. An electron projected perpendicular to the field goes in a circle. Assuming Bohr's quantization rule for angular momentum, calculate (a) the smallest possible radius of the electron (b) the radius of the nth orbit and (c) the minimum possible speed of the electron.
Which expression gives the angular momentum allowed by Bohr’s second postulate?
What happens when a string is plucked?
Which wavelengths survive in a plucked string?
What is the electron’s de Broglie wavelength when its momentum magnitude is \[mv_n\]?
What does de Broglie’s standing-wave argument explain about a hydrogen atom?
Which two-electron atom cannot be explained by extending Bohr’s model?
Which electrical force is included in the Bohr model?
What property of spectral lines can Bohr’s model not explain, despite predicting frequencies for hydrogenic atoms?
