Advertisements
Advertisements
Question

As shown in the figure, Avinash is standing near his house. He can choose from two roads to go to school. Which way is shorter? Explain why.
Advertisements
Solution
In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, in △ABC, AC < AB + BC.
Hence, the shortest way to reach school is via AC.
RELATED QUESTIONS
Can a triangle have All angles equal to 60°? Justify your answer in case.
Compute the value of x in the following figure:

In the given figure, side BC of ΔABC is produced to point D such that bisectors of ∠ABC and ∠ACD meet at a point E. If ∠BAC = 68°, find ∠BEC.

State, if the triangle is possible with the following angles :
125°, 40°, and 15°
Find the unknown marked angles in the given figure:

Find the unknown marked angles in the given figure:

One angle of a right-angled triangle is 70°. Find the other acute angle.
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
15 cm, 20 cm, 25 cm
What is the sum of the measures of the interior angles of any triangle, △ABC?
How is a vertex of triangle △ABC most accurately defined?
