Advertisements
Advertisements
प्रश्न

As shown in the figure, Avinash is standing near his house. He can choose from two roads to go to school. Which way is shorter? Explain why.
Advertisements
उत्तर
In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, in △ABC, AC < AB + BC.
Hence, the shortest way to reach school is via AC.
संबंधित प्रश्न
In Fig. 10.25, AB = AC and DB = DC, find the ratio ∠ABD : ∠ACD.
In the given figure, if AB || CD, EF || BC, ∠BAC = 65° and ∠DHF = 35°, find ∠AGH.

In ΔABC, if bisectors of ∠ABC and ∠ACB intersect at O at angle of 120°, then find the measure of ∠A.
Mark the correct alternative in each of the following:
If all the three angles of a triangle are equal, then each one of them is equal to
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
12 cm, 12 cm, 16 cm
Draw a rough sketch of a triangle ABC. Mark a point P in its interior and a point Q in its exterior. Is point A in its exterior or in its interior?
Identify three triangles in the figure.
How many sides does a triangle have?
What is the sum of the measures of the interior angles of any triangle, △ABC?
How is a vertex of triangle △ABC most accurately defined?
