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Question
Arrange the following compounds in increasing order of their property as indicated:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)
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Solution
Carboxylic acid molecules with electron-withdrawing groups or electronegative atoms are more acidic. In addition, bonding the atom/group further away from the a-carbon reduces acidity. Thus, the acid strength is:
\[\begin{array}{cc}
\phantom{.....................................}\ce{Br}\phantom{.......................}\ce{Br}\\
\phantom{....................................}|\phantom{.........................}|\\
\ce{\underset{I}{(CH3)2CHCOOH} < \underset{II}{CH3(CH2)2COOH} < \underset{III}{CH3CHCH2COOH} < \underset{IV}{CH3CH2CHCOOH}}\
\end{array}\]
The lesser number of −CH3 groups on the α-carbon in II results in increased acidity compared to I. The −CH3 group increases electron density through the +I action on α-carbon which also affects the −COOH group, hindering the release of H+.
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\[\begin{array}{cc}
\ce{O}\phantom{...............................................}\\
||\phantom{...............................................}\\
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