Advertisements
Advertisements
Question
Which acid of the pair shown here would you expect to be stronger?
CH2FCH2CH2CO2H or CH3CHFCH2CO2H
Advertisements
Solution
| \[\begin{array}{cc} \phantom{...................}\ce{O}\\ \phantom{...................}||\\ \ce{\underset{4-Fluorobutanoic acid}{F <- CH <- CH2 <- CH2 <- C <- O <- H}}\ \end{array}\] |
\[\begin{array}{cc} \ce{CH3}\phantom{..............}\ce{O}\phantom{........}\\ \phantom{.}|\phantom{.................}||\phantom{........}\\ \ce{\underset{3-Fluorobutanoic acid}{F <- CH <- CH2 <- C <- O <- H}}\ \end{array}\] |
The inductive effect decreases with distance, so −I effect of F is stronger in 3-fluorobutanoic acid than in 4-fluorobutanoic acid. Hence, CH3CHFCH2COOH is stronger acid than FCH2CH2CH2COOH.
APPEARS IN
RELATED QUESTIONS
How is 1-nitropropane prepared from suitable oxime?
Why pKa of F-CH2-COOH is lower than that of Cl−CH2−COOH?
Distinguish between the following : Benzoic acid and methyl benzoate
Which acid of the pair shown here would you expect to be stronger?
CH2FCO2H or CH2ClCO2H
Which acid of the pair shown here would you expect to be stronger?

Arrange the following compounds in increasing order of their property as indicated:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)
Arrange the following compounds in increasing order of their property as indicated:
Benzoic acid, 4-Nitrobenzoic acid, 3, 4-Dinitrobenzoic acid, 4-Methoxybenzoic acid (acid strength)
What happens when Salicylic acid is treated with (CH3CO)2 O/H+?
Assertion: Formaldehyde is a planar molecule.
Reason: It contains sp2 hybridised carbon atom.
Acidity of BF3 can be explained on the basis of which of the following concepts?
A mixture of benzaldehyde and formaldehyde on heating with 50% NaOH solution gives
When propionamide reacts with Br2 in the presence of alkali the product is ______.
Formic acid and formaldehyde can be distinguished by treating with ______.
Describe the action of alcoholic potassium hydroxide (alc. KOH) on ethyl bromide
Describe the action of alcoholic potassium hydroxide (alc. KOH) on n-propyl bromide
Describe the action of alcoholic potassium hydroxide (alc. KOH) on isopropyl bromide.
An ester is boiled with KOH. The product is cooled and acidified with conc. HCL. A white crystalline acid separates. The ester is:
