Advertisements
Advertisements
Question
Arrange in ascending order:
25, 33, 23 × 2, (33)2, 35, 40, 23 × 31
Advertisements
Solution
In ascending order, the numbers are arranged from smallest to largest.
We have, 25 = 2 × 2 × 2 × 2 × 2 = 32
33 = 3 × 3 × 3 = 27
23 × 2 = 2 × 2 × 2 × 2 = 16
(33)2 = 33 × 2 ...[∴ (am)n = amn]
36 = 3 × 3 × 3 × 3 × 3 × 3 = 729
35 = 3 × 3 × 3 × 3 × 3 = 243
4° = 1 ...[∴ a0 = 1]
And 23 × 31 = 2 × 2 × 2 × 3 = 24
Thus, the required ascending order will be 4° < 23 × 2 < 23 × 31 < 33 < 25 < 35 < (33)2.
APPEARS IN
RELATED QUESTIONS
Simplify:
`(3^4)^-2`
Simplify:
`((2/5)^-2)^-3`
Simplify:
`[(3/4)^6]^1`
Write the following number using positive indices.
`(2/7)^-2`
If 2m – 1 + 2m + 1 = 640, then find m
Simplify using law of exponents.
(xm)0
240 + 240 is equal to
Which of the following is not equal to `((-5)/4)^4`?
`(6/13)^10 ÷ [(6/13)^5]^2 = (6/13)^-`
Arrange in descending order:
22+3, (22)3, 2 × 22, `3^5/3^2`, 32 × 30, 23 × 52
