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Question
Write the following numbers using positive indices.
`(11/3)^-5`
Sum
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Solution
It is known that, `"a"^-"m" = 1/"a"^"m"` where m is an integer and a is a non-zero rational number.
`(11/3)^-5`
`= 1/(11/3)^5`
`= (3/11)^5`
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RELATED QUESTIONS
Using laws of exponents, simplify and write the answer in exponential form:
(34)3
Simplify:
`((2/5)^-2)^-3`
Simplify:
`(6^5)^4`
Simplify:
`[(5/8)^3]^-2`
Simplify:
`[(3/4)^6]^1`
Solve: `((2/5)^(-2))^3`.
Using the power rule, (37)−2 = 35
62 × 6m = 65, find the value of ‘m’
`[((-1)/4)^16]^2 = ((-1)/4)^-`
34 > 43
