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Question
Write the following numbers using positive indices.
`(1/6)^-3`
Sum
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Solution
It is known that, `"a"^-"m" = 1/"a"^"m"` where m is an integer and a is a non-zero rational number.
`(1/6)^-3`
`= 1/(1/6)^3`
`= (6/1)^3`
`= 6^3`
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RELATED QUESTIONS
Simplify:
`[(15/12)^3]^4`
Simplify:
`(6^5)^4`
Simplify:
`[(2/5)^-3]^2`
Write the following number using positive indices.
`(2/7)^-2`
Solve: `((2/5)^(-2))^3`.
Simplify using law of exponents.
(64)3
(–3)4 = –12
34 > 43
Arrange in ascending order:
25, 33, 23 × 2, (33)2, 35, 40, 23 × 31
Arrange in descending order:
22+3, (22)3, 2 × 22, `3^5/3^2`, 32 × 30, 23 × 52
