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Question
Arrange in descending order:
22+3, (22)3, 2 × 22, `3^5/3^2`, 32 × 30, 23 × 52
Sum
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Solution
In descending order, the numbers are arranged from largest to smallest.
We have, 22+3 = 25 = 2 × 2 × 2 × 2 × 2 = 32
(22)3 ⇒ 26 = 2 × 2 × 2 × 2 × 2 × 2 = 64
2 × 22 = 21+2 ⇒ 23 = 8
`3^5/3^2` = 35–2 ⇒ 33 = 27
32 × 30 = 32+0 ⇒ 32 = 9
23 × 52 = 2 × 2 × 2 × 5 × 5 ⇒ 8 × 25 = 200
Thus, the required descending order will be (22 × 52) > (22)3 > 22+3 > `3^5/3^2` > (32 × 30 ) > (2 × 22).
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