Question

Arrange in descending order:

2²⁺³, (2²)³, 2 × 2², `3^5/3^2`, 3^{2 ×} 3⁰, 2³ × 5²

Answer 1

In descending order, the numbers are arranged from largest to smallest.

We have, 2²⁺³ = 2⁵ = 2 × 2 × 2 × 2 × 2 = 32

(2²)³ ⇒ 2⁶ = 2 × 2 × 2 × 2 × 2 × 2 = 64

2 × 2² = 2¹⁺² ⇒ 2³ = 8

`3^5/3^2` = 3^5–2 ⇒ 3³ = 27

3² × 3⁰ = 3²⁺⁰ ⇒ 3² = 9

2³ × 5² = 2 × 2 × 2 × 5 × 5 ⇒ 8 × 25 = 200

Thus, the required descending order will be (2² × 5²) > (2²)³ > 2²⁺³  > `3^5/3^2` > (3² × 3⁰ ) > (2 × 2²).