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प्रश्न
Write the following numbers using positive indices.
`(1/6)^-3`
योग
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उत्तर
It is known that, `"a"^-"m" = 1/"a"^"m"` where m is an integer and a is a non-zero rational number.
`(1/6)^-3`
`= 1/(1/6)^3`
`= (6/1)^3`
`= 6^3`
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Simplify:
`[(5/8)^3]^-2`
Simplify:
`[(3/4)^6]^1`
Write the following number using positive indices.
`(2/7)^-2`
Solve for x: `(2^(2x - 1))/(2^(x + 2))` = 4
How many zeros are there in 10010?
Which of the following is not equal to `((-5)/4)^4`?
`[(7/11)^3]^4 = (7/11)^-`
34 > 43
Arrange in ascending order:
25, 33, 23 × 2, (33)2, 35, 40, 23 × 31
Arrange in descending order:
22+3, (22)3, 2 × 22, `3^5/3^2`, 32 × 30, 23 × 52
