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प्रश्न
Write the following numbers using positive indices.
`(1/6)^-3`
योग
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उत्तर
It is known that, `"a"^-"m" = 1/"a"^"m"` where m is an integer and a is a non-zero rational number.
`(1/6)^-3`
`= 1/(1/6)^3`
`= (6/1)^3`
`= 6^3`
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Using laws of exponents, simplify and write the answer in exponential form:
(34)3
Simplify:
`((2/5)^-2)^-3`
Simplify:
`[(6/7)^5]^2`
Simplify:
`[(2/3)^-4]^5`
Simplify:
`[(5/8)^3]^-2`
Solve: `(7^(- 2))^(-5)`
Simplify and express the following in exponential form:
45 × 42 × 44
Which of the following is not equal to 1?
`[((-1)/4)^16]^2 = ((-1)/4)^-`
34 > 43
