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प्रश्न
Write the following numbers using positive indices.
`(1/6)^-3`
योग
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उत्तर
It is known that, `"a"^-"m" = 1/"a"^"m"` where m is an integer and a is a non-zero rational number.
`(1/6)^-3`
`= 1/(1/6)^3`
`= (6/1)^3`
`= 6^3`
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
Say true or false and justify your answer:
23 > 52
Simplify:
`(6^5)^4`
Simplify:
`[(2/3)^-4]^5`
Simplify:
`[(2/5)^-3]^2`
Write the following numbers using positive indices.
`(11/3)^-5`
Solve for x: `(2^(2x - 1))/(2^(x + 2))` = 4
Which of the following is not equal to `((-5)/4)^4`?
`[(7/11)^3]^4 = (7/11)^-`
`[((-1)/4)^16]^2 = ((-1)/4)^-`
Arrange in descending order:
22+3, (22)3, 2 × 22, `3^5/3^2`, 32 × 30, 23 × 52
