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Question
`[((-1)/4)^16]^2 = ((-1)/4)^-`
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Solution
`[((-1)/4)^16]^2 = ((-1)/4)^bb(underline(32)`
Explanation:
Here, `[((-1)/4)^16]^2 = ((-1)/4)^(16 xx 2)` ...[∵ (am)n = amn]
= `((-1)/4)^32`
∴ `[((-1)/4)^16]^2 = ((-1)/4)^32`
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