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प्रश्न
Arrange in ascending order:
25, 33, 23 × 2, (33)2, 35, 40, 23 × 31
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उत्तर
In ascending order, the numbers are arranged from smallest to largest.
We have, 25 = 2 × 2 × 2 × 2 × 2 = 32
33 = 3 × 3 × 3 = 27
23 × 2 = 2 × 2 × 2 × 2 = 16
(33)2 = 33 × 2 ...[∴ (am)n = amn]
36 = 3 × 3 × 3 × 3 × 3 × 3 = 729
35 = 3 × 3 × 3 × 3 × 3 = 243
4° = 1 ...[∴ a0 = 1]
And 23 × 31 = 2 × 2 × 2 × 3 = 24
Thus, the required ascending order will be 4° < 23 × 2 < 23 × 31 < 33 < 25 < 35 < (33)2.
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संबंधित प्रश्न
Using laws of exponents, simplify and write the answer in exponential form:
(34)3
Simplify:
`((1/7)^-3)^4`
Simplify:
`[(2/5)^-3]^2`
Solve: `((2/5)^(-2))^3`.
Using the power rule, (37)−2 = 35
Solve for x: `(2^(2x - 1))/(2^(x + 2))` = 4
Simplify and express the following in exponential form:
45 × 42 × 44
Which of the following is not equal to 1?
`[(7/11)^3]^4 = (7/11)^-`
Arrange in descending order:
22+3, (22)3, 2 × 22, `3^5/3^2`, 32 × 30, 23 × 52
