Advertisements
Advertisements
Question
Apply first law for an isobaric process.
Advertisements
Solution
The first law of thermodynamics for an isobaric process is given by ∆U = Q – P∆V
W = P∆V, ∆U = `"Q" - μ"RT"_"f" [1 - "T"_"i"/"T"_"f"]`
APPEARS IN
RELATED QUESTIONS
An ideal gas is taken through an isothermal process. If it does 2000 J of work on its environment, how much heat is added to it?
Differentiate between the reversible and irreversible processes.
Explain the thermodynamics of the isochoric process.
Draw the PV diagram for the isobaric process.
Draw the PV diagram for the isochoric process.
What are the limitations of the first law of thermodynamics?
An ideal gas is made to go from a state A to stale B in the given two different ways (see figure) (i) an isobaric and then an isochoric process and (ii) an isochoric and then an isobaric process. The work done by gas in the two processes are W1 and W2 respectively. Then,

Two identical samples of a gas are allowed to expand (i) isothermally (ii) adiabatically. Work done is ____________.
Consider P-V diagram for an ideal gas shown in figure.

Out of the following diagrams (figure), which represents the T-P diagram?
![]() (i) |
![]() (ii) |
![]() (iii) |
![]() (iv) |
In the figure shown here, the work done in the process ACBA is ______.





