Advertisements
Advertisements
प्रश्न
Apply first law for an isobaric process.
Advertisements
उत्तर
The first law of thermodynamics for an isobaric process is given by ∆U = Q – P∆V
W = P∆V, ∆U = `"Q" - μ"RT"_"f" [1 - "T"_"i"/"T"_"f"]`
APPEARS IN
संबंधित प्रश्न
Answer in brief.
Why should a Carnot cycle have two isothermal two adiabatic processes?
For work done to be reversible, the process should be ______
Differentiate between the reversible and irreversible processes.
Consider the following cyclic process consist of isotherm, isochoric and isobar which is given in the figure.
Draw the same cyclic process qualitatively in the V-T diagram where T is taken along the x-direction and V is taken along the y-direction. Analyze the nature of heat exchange in each process.
An ideal gas is made to go from a state A to stale B in the given two different ways (see figure) (i) an isobaric and then an isochoric process and (ii) an isochoric and then an isobaric process. The work done by gas in the two processes are W1 and W2 respectively. Then,
In which of the following processes, beat is neither absorbed nor released by a system?
For an isothermal expansion of a perfect gas, the value of `(Delta "P")/"P"` is equal to ____________.
Ideal gas for which 'ϒ' = 1.5 is suddenly compressed to `1/4`th of its initial volume. The ratio of 4 the final pressure to the initial pressure is ______.
`(ϒ = "C"_"p"/"C"_"v")`
Which of the following processes is reversible?
Explain the thermodynamic process.
